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Lead (II) bromide comprises of Pb2+ and Br- ions which are held together by strong ionic bonds. |
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When lead(II) bromide melts, Pb2+ and Br- ions are released from their bonds and become freely moving particles as shown in the following equation:
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PbBr2(s) → Pb2+(l) + 2Br-(l) |
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During electrolysis, Pb2+ ions are attracted to the cathode while Br- ions the move the anode. |
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At the anode, Br- ions lose their electrons:
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2Br-(l) → Br2(g) + 2e- |
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A brown gas, bromine is formed. |
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At the cathode, Pb2+ ions receive electrons to form lead, a shinning grey metal.
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The overall equation is:
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Pb2+(l) + 2Br-(l) → Pb(s) + Br2(g) |
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